In this article I am representing 20 word problems with fractions. these problems are very useful for grade 5 or grade 6 students, especially beginners.
Table of Contents
Addition Word Problems With Fractions
Problem: Kevin has \(\frac{1}{3}\) of a pizza. Sara gave him \(\frac{1}{4}\) of another pizza. How much amount pizza does Kevin have in total?
Answer: Total amount of pizza = \(\frac{1}{3} + \frac{1}{4}\) = \(\frac{4}{12} + \frac{3}{12}\) = \(\frac{7}{12}\)
So, Kevin has \(\frac{7}{12}\) pizza in total
Problem: Anna has two cups with \(\frac{1}{2}\) liter and \(\frac{1}{5}\) liter. How much water can Anna carry with these cups?
Answer: Amount of water Anna can carry = \(\frac{1}{2} + \frac{1}{5}\) = \(\frac{5}{10} + \frac{2}{10}\) = \(\frac{7}{10}\)
So, with her two cups, Anna can transport \(\frac{7}{10}\) litter water.
Problem: Jain is a fruit shop owner. he sold \(\frac{55}{4}\) kg of mango in the morning, \(\frac{21}{2}\) kg of mangos in the afternoon, and 11 kg of mangos in the evening. How many mangoes did he sell in total?
Answer: Total mango sold by Jain = Sold in the morning + Sold in afternoon + Sold in evening = \(\frac{55}{4}\) + \(\frac{21}{2}\) + 11 = \(\frac{55}{4}\) + \(\frac{42}{4}\) + \(\frac{44}{4}\) = \(\frac{55+42+44}{4}\) = \(\frac{141}{4}\)
So, Jain sold \(\frac{141}{4}\) kg of mangos.
Problem: If Anna added \(\frac{1}{4}\) kg of apples, \(\frac{1}{2}\) kg of mangoes, and \(\frac{3}{5}\) kg of grapes to a fruit salad, how much fruits did she add to the fruits salad?
Answer: Total fruits in fruits salad = Weight of apple + Weight of mangoes + Weight of grapes = \(\frac{1}{4}\) + \(\frac{1}{2}\) + \(\frac{3}{5}\) = \(\frac{5}{20}\) + \(\frac{10}{20}\) + \(\frac{12}{20}\) = \(\frac{27}{20}\)
So, Anna added \(\frac{27}{20}\) kg of fruits in the fruits salad
Problem: Smith has finished \(\frac{3}{7}\)th of work, and Tony has finished \(\frac{2}{5}\)th of the same work. then how much work have they completed?
Answer: Completed work = Smith’s work + Tony’s work = \(\frac{3}{7}\) + \(\frac{2}{5}\) = \(\frac{15}{35}\) + \(\frac{14}{35}\) = \(\frac{29}{35}\)
So they have completed \(\frac{29}{35}\)th of the work
Subtraction Word Problems With Fractions
Problem: Sera’s mother gives her an apple. She ate \(\frac{2}{5}\)th of the apple. How much of the apple is still in his hand?
Answer: Apple left in Sera’s hand = Number of apples – Portion ate by Anna = \(1 – \frac{2}{5}\) = \(\frac{5}{5} – \frac{2}{5}\) = \(\frac{3}{5}\)
So, Sera still have \(\frac{3}{5}\)th of the apple
Problem: Jhon went to the store and purchased \(\frac{3}{2}\) kg of rice. He gave Sam 1 kg of rice; how much rice was left in Jhon’s hand after that?
Answer: Rice left in Jhon’s hand = Total rice – Sam’s rice = \(\frac{3}{2} – 1\) = \(\frac{3}{2} – \frac{2}{2}\) = \(\frac{1}{2}\)
So, Jhon has \(\frac{1}{2}\) kg rice left in his hand
Problem: A steel rod is \(\frac{7}{3}\) meters long. Alex took \(\frac{5}{4}\) meters from the steel rod, and Jhon took \(\frac{3}{5}\) meters from the remaining potion. How much length remains in the steel rod?
Answer: Length remains in the steel rod = Length of the steel rod – Length steel rod was taken by Alex – Length of steel rod taken by Jhon
Length remains in the steel rod = \(\frac{7}{3}\) – \(\frac{5}{4}\) – \(\frac{3}{5}\) = \(\frac{140}{60}\) – \(\frac{75}{60}\) – \(\frac{36}{60}\) = \(\frac{140-75-36}{60}\) = \(\frac{29}{60}\)
Then the remaining portion of the steel rod is \(\frac{29}{60}\) meter
Problem: If Jacob lost \(\frac{3}{2}\) dollars from \(\frac{11}{2}\) dollars, how much money was left in his hand?
Answer: Money left in Jacob’s hand = Total money – Lost money = \(\frac{11}{2}\) – \(\frac{3}{2}\) = \(\frac{8}{2}\) = 4
So, $4 is left in Jacob’s hand
Problem: Jane ran \(\frac{7}{2}\) km and Jack ran \(\frac{10}{3}\) km. Who ran the longest distance and what was the difference?
Answer: Jane runs more distance than Jack (how?)
\(\frac{7}{2}\) = \(\frac{21}{6}\)
\(\frac{10}{3}\) = \(\frac{20}{6}\)
then \(\frac{7}{2}\) > \(\frac{10}{3}\) so, Jane runs more distance than Jack
The difference = Jane’s distance – Jack’s distance = \(\frac{7}{2} – \frac{10}{3}\) = \(\frac{21}{6} – \frac{20}{6}\) = \(\frac{1}{6}\)
Multiplication Word Problems With Fractions
Problem: Charles sent to bring \(\frac{7}{2}\) litter milk from the shop. But on the way back he lost 30% milk on the road. How many liters of milk did he lose?
Answer: lost milk = \(\frac{7}{2} \times \frac{30}{100}\) = \(\frac{7}{2} \times \frac{3}{10}\) = \(\frac{21}{20}\)
So, Charles lost \(\frac{21}{20}\) liter milk
Problem: A square feet of glass costs $\(\frac{11}{2}\). Alex required \(\frac{30}{7}\) square feet of glass. So, how much money does he require to purchase the glass?
Answer: Total cost = required glass × cost of glass (per square feet) = \(\frac{30}{7} \times \frac{11}{2}\) = \(\frac{330}{14}\) = \(\frac{165}{7}\)
So, Alex needs $\(\frac{165}{7}\) to buy \(\frac{30}{7}\) square feet of glass
Problem: Charlie can build \(\frac{5}{2}\) meters of the wall in one hour. He will work \(\frac{13}{2}\) hours per day. then find the length of the wall he built in 4 days
Answer: Length of the wall Charlie build in 4 days = 4 × Length of the wall Charlie build in 1 day
Length of the wall Charlie built in 1 day = Charlie’s working time in one-day × Length of the wall he build in one hour = \(\frac{13}{2} \times \frac{5}{2}\) = \(\frac{65}{4}\)
Length of the wall Charlie build in 4 days = \(4 \times \frac{65}{4}\) = 65
So, charlie can build 65 meters of the wall in 4 days
Problem: Anna is walking \(\frac{7}{2}\) miles per hour. then how many miles she can walk in \(\frac{5}{2}\) hours
Answer: Distance after \(\frac{5}{2}\) hours = Walking distance (per hour) × Time = \(\frac{7}{2} \times \frac{5}{2}\) = \(\frac{35}{4}\)
So, Anna will walk \(\frac{35}{4}\) miles in \(\frac{5}{2}\) hours
Problem: A shopkeeper sorted his apples into 21-packet packets. The weight of each packet is \(\frac{3}{2}\) kg. How many apples are there in the shop?
Answer: Total apple = Number of packets × Weight of the packet = 21 × \(\frac{3}{2}\) = \(\frac{63}{2}\)
So, \(\frac{63}{2}\) kg of apple is present in the shop
Division Word Problems With Fractions
Problem: Find the size of each rope after a \(\frac{19}{2}\) meter cord is cut into 20 pieces.
Answer: Length of cut code = Total length of code / Number of pieces = \(\frac{\frac{19}{2}}{20}\) = \(\frac{19}{40}\) meters
Problem: John and Sara are sharing \(\frac{1}{2}\) of a pizza. How much will each of them receive?
Answer: Jhon’s and Sara’s pizza = Total pizza / Number peaple = \(\frac{\frac{1}{2}}{2}\) = \(\frac{1}{4}\)
Problem: A man attempts to fill a cup of volume \(\frac{4}{3}\) liter from a bucket of water with a \(\frac{1}{18}\) liter spoon. How many times does he have to take water from the bucket?
(\(\frac{4}{3}\) and \(\frac{1}{18}\) are volume of the cup and spoon respectively)
Answer: Number of times he needs to take water = Volume of cup / Volume of spoon = \(\frac{\frac{4}{3}}{\frac{1}{18}}\) = \(\frac{4}{3} \times \frac{18}{1}\) = 24
So the man needs to take 24 spoons of water to fill the cup
Problem: Michel can build a \(\frac{9}{4}\) meter wall in \(\frac{3}{2}\) hour. How long did it take him to build a one-meter wall?
Answer: Time to build 1 meter wall = Total time / Total length of the wall = \(\frac{\frac{3}{2}}{\frac{9}{4}}\) = \(\frac{3}{2} \times \frac{4}{9} \) = \(\frac{2}{3}\)
So, Michel will take \(\frac{2}{3}\) hours to build a one-meter wall
Problem: Sam walked \(\frac{9}{2}\) kilometers in \(\frac{4}{3}\) hours. How many kilometers did he walk in an hour?
Answer: Sam’s walking distance in 1 hour = Distance walked / Time = \(\frac{\frac{9}{2}}{\frac{4}{3}}\) = \(\frac{9}{2} \times \frac{3}{4}\) = \(\frac{27}{4}\)
So, Sam will walk \(\frac{27}{4}\) kilometers per hour
